X^2+8/x+2=x^2-2x+4

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Solution for X^2+8/x+2=x^2-2x+4 equation: 



X^2+8/X+2=X^2-2X+4

We move all terms to the left:

X^2+8/X+2-(X^2-2X+4)=0



Domain of the equation: X!=0

X∈R



We get rid of parentheses

X^2-X^2+8/X+2X-4+2=0

We multiply all the terms by the denominator


X^2*X-X^2*X+2X*X-4*X+2*X+8=0

We add all the numbers together, and all the variables

X^2*X-X^2*X-2X+2X*X+8=0

Wy multiply elements

X^3-1X^3+2X^2-2X+8=0

We do not support eXpression: X^3

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